Value of the Signal for Flux with Continuous Spectrum If the expected value of flux at time t is given by

Подпись: (3-43)®(t) = Ф + 0 (t) ,

Ak*Qe2Zi22

Подпись: S(t) = Подпись: Ak42zi22
image195

where Ф is the time-averaged value and <j>{t) has a power spectral density of G(w), then the time-averaged value of the signal from an a-c system, using Equation (3-51) for v(t) and Equation (3-46) for S(t), is. •

image196

Since the first term on the right is the output due to the time-averaged flux, the second term represents the error due to the fluctuations of the flux. The fractional error is the ratio of these two terms: .

3,2.5 Value of the Signal for Transient in the Flux

In this section the expected value of the signal will be calculated for the case in which v(t) is given by Equation (3-51) and for three different transients in the flux.

The procedure that will be followed is:

a. Substitution of v(t) f Equation (3-51) J and the appropriate expression for <b(t) into Equation (3-49) to obtain < AV2 (t)> ;

b. Simplification of this expression for <AV2(t)>; .

2

c. Substitution of the simplified expression for <AV (t)>and the proper initial condition into the differential Equation (3-2) of the integrating circuit to obtain the expected value

. of the signal. <S(t)>; and

d. Simplification of <S(t) >. .

Case 1. The flux has one constant value for t<o and a second constant value for t>o; i. e

Подпись: *(t)for t < o, and

image198

®(t) = Ф0 + Д Ф for t > o.

Подпись: 2 Ак(Ф + ДФ) Q 2Z122 <AVz(t)> = °^—ii— image200

So Equation (3-61) becomes

Подпись: HА(кДФ Qe Z12r ш

image202

A k *o °e2 Z122

image203

(шн + u’i).

 

yields the expected value of the signal

 

<S(t)>

 

Шн + WL

 

А кдф Qe2 Z122

 

image204
image205

WH + a, L

 

А (кДФОе Z12)^
2t

 

-t/r

 

image206
image207

Since the correct value is

 

image208
image209
image210

Шн + a, L

 

the error is E(t)

 

А к ДФ Qe2Z’i22 ‘-h2

 

-t/r

e

 

WH+WL

 

image211

-t/т

 

image212

wi>,H + a, L>

 

2t

 

and the fractional error is

 

image213

Ф(0 = Фг

 

for t < o, and

 

ФМ = Ф0 + St for t >o,

 

then <Ht) = St , d(t-x) = St-Sx. and the expected value of Av (t) is

 

А к(Ф0 + St) Qe2 Z122

 

<AV2(t)> =

 

H

 

image214
image215

— AkSQe2Z122

 

WH-WL

 

image216

image217 image218 image219 Подпись: (3-67)

-2ш1}

This expression approaches, with a time-constant of about l/w^, the simpler one

Подпись:Подпись:Подпись:Подпись: + A2

H

Подпись:/kSQeZj2

Ш.

image226

and, if t >l/wL, this simpler expression may be substituted into Equation (3-2) along with the initial condition

image227
image228

to obtain the expected value of the signal

Подпись: (3-69)* (i.. -,л’

Подпись: the error is E(t) image231 image232

Since the correct value is

il* Ш-±)— ( 1 — e-t/T ) .

Подпись:Подпись: Ъ +^_ ( 1 . e-t/r

image235 Подпись: (3-72)

and the fractional error is

Подпись: E(t) image238 image239 Подпись: (3-73)

Since we have assumed that т » l/w.^, this may be simplified to

Case 3. The flux is constant for t < о and increases exponentially (constant period, P) for t >o; i. e., ‘

®(t) = Ф0

for t<o, and

®'(t) = Ф0 et/p

for t>o,

then <(>(t) = Ф0(е1/,р-1), 0(t-x) = (e^’x^P-l), and the expected value of AV2(t) is

JH 2Р(ШН + Ші) (2P WHWL + РшН + PwL + t/P

Подпись: , АкФ О 2Z.,2 <AV2(t)> = 12-

image242 image243 Подпись: (3-74) Подпись: 2t/P

шн + wL . (2Po>H + 1)(2Pwl + l)(PwH + Po>L + 1)

This is really the simplified expression for <AV^(t)>. The actual expression approaches this simpler one with a time constant of about 1/cuSo, if | P| l/o^ and т 3> 1/w^, this simpler Equation (3-74) may be substituted into the differential Equation (3-2) along with the initial condition

Подпись: AMI0 «є2 2ігг 2 .. 2

Подпись:<S(o)> =

Подпись: <S(t)> image249 Подпись: ,-t/T Подпись: (3-75)

to obtain the expected value of the a-c system signal

Подпись: G = Подпись: Ak®oQe2zi22 image254

where

Подпись: H =2P2(wh+wl)(2P2whcjl + Pwh+Pojl + 1)

(P + t) (2PwH+l) (2Pwl+1) (Ршн+Ршь+1)’

image256

and

Since the correct value is

Подпись: (3-76)Подпись:<S(t)>c = Get/P,

the error is.

. E(t) = G(H-l)(et/P-e’t/T ) + J (e2t/P-e’t//T ),’

image259 Подпись: (3-78)
image261

and the fractional error is

( е‘/р-е-*(т+І)