The amount of ethanol produced in the SSF fermentations is calculated based on the weight loss as a result of CO2 formation in the reaction shown below.

C6H1206 ^2C2H50H + 2C02 (1)

The resulting formula is derived as below, using the molar masses of ethanol and CO2 of 46.07 g/mol and 44.01 g/mol, respectively:

(С6Я1005)пЯ20 + (n — 1)Я20 ^ nC6H1206 (4)

Where n is in the range 2000 — 10000. The highest ethanol yield is obtained when the cellulose is completely hydrolyzed into glucose and fermented into ethanol as shown in Equation 1 and 4. We now consider the number of monomers (n) in one gram of cellulose. Under complete hydrolysis this amount of matter becomes the amount of glucose. From equation 1 it can be seen that the amount of ethanol produced is 0.512 g per g of glucose fermented. The potential weight of ethanol from 1 g of cellulose is 0.569 g (Equation 5).

= 2М*Ш 2 x 46.1 = ncrj" (5)

iiel&ethanoifromceiiuiose = Mw = 162 =0m579l9 ( )

W(C6H10O5)